Spencer Heath Archive

Item 308

Penciling on notepad paper concerning energy.

No date

 

 

 

A force of 1 dyne acting for 1 second is the force that can move 1 gram from 0 velocity to 1 cm per sec velocity. To do this it must move that gram ½ cm in 1 sec.

 

This is 1 dyne x ½ cm x 1 sec

This is ½ dyne-cm x 1 sec (action)

This is ½ dyne-cm(energy) = 1 erg

 

When X = 4. Then a gram has been raised from 0 to 4 cm per sec.

Average velocity was 2 per sec. So the energy imparted to the gram was the force of a dyne acting through 2 cm. So E = 2 dyne-cm. But more than 1 sec is required to give a velocity of 4. The velocity must be raised 4 times. So the energy will be 4 times

2 dyne-cm = 8 dyne-cm ____ which is 16 ergs