Spencer Heath Archive

Item 268

Note paper inserted in Hans Reichenbach, Atom and Cosmos

April 1961?

 

Mass 2    Motion 4    Time 8

Total 64 units of action — ergs.

Omit mass —

(Motion 4)/(Time 8)

v = ½

v² = ¼

vt = ½ x 8 = 8/2 = 4/1

Mass-Motion      Force-Distance
 2×4                                2×4

Mass per unit of motion = 2

Motion per unit of time = 4

Number of Work units per unit of time = 8

Total number of Work units = 8 x 8 = 64  Same as 2x4x8 = 64

V = 4    V² = 16

Ratio of mass to motion

Masses 2 per motions 1

Ratio of motion to time V

V = Motions 4 per intervals 1 (seconds)

To attain V = 4 required 4 units of time

So V x V or V² is the same as V x t

which for 1 unit of force gives 16 units of work

and for 2 units of force gives 32 units of work.