Spencer Heath Archive

Item 392

November 13, 1944

M = 1 gram moves from 0 to rate of 1 cm per sec

Force required is one dyne

Distance moved was 2 centimeters

Time required was 4 seconds

Average velocity was ½ centimeter per second

Final velocity was one centimeter per second

E = Energy = dynes times centimeters/2 = Ergs

Rate of Energy = Energy, Ergs, in one second

Quantity of E = number of Ergs times number of seconds

 

 

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One gram moving at rate of one centimeter per second possesses how much Energy?

E = MV²/2 = 1 x 1²/2. Ergs in one second

E = one dyne times 2 centimeters = one Erg

Requires 4 seconds (in this case)

E (as rate) = (1 dyne x 2 cm)/4 sec = ½ erg per second

1 dyne times 1 cm = ½ erg

Mass in grams times centimeters in one second equals half the number of Ergs in one second. So Mass in grams times number of centimeters equals half the number of ergs. There are twice as many Ergs as centimeters because it took 2 centimeters of movement to bring the gram up to a movement of one centimeter in one second. (?)